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m va n natural sonlar uchun EKUK(m;n)=480 ; m-n=66 o'rinli bo'lsa, EKUB(m;n)+m+n=?

@mathematica0606

Uchta merganning o'qni nishonga tekkizish ehtimollari mos ravishda 0.4 0.7 va 0.8 ga teng. Demak P(a)=0.4 P(b)=0.7 va P(c)=0.8 Bu merganlar baravariga o'q uzganda:

Savol:

1. Hech birining nishonga tekkiza olmaslik ehtimolini toping. Yechim: P(d)=[1-P(a)]•[1-P(b)]•[1-P(c)]=0.6•0.3•0.2=0.036

2. Uchalasining ham o'qni nishonga tekkizish ehtimolini toping. Yechim:
   P(f)=P(a)•P(b)•P(c)=0.4•0.7•0.8=0.224

3. Birinchi mergan nishonga tekkizib, ikkinchi va uchinchi merganlar nishonga tekkiza olmaslik ehtimolini toping. Yechim:
   P(g)=P(a)•[1-P(b)]•[1-P(c)]=0.4•0.3•0.2=0.024

4. Ikkinchi merganniki tegib birinchi va uchinchi merganniki tegmaslik ehtimoli

P(h)=[1-P(a)]•P(b)•[1-P(c)]

1. Uchinchi merganniki tegib, birinchi va ikkinchi merganniki tegmaslik ehtimoli

P(j)=[1-P(a)]•[1-P(b)]•P(c)

6.Birinchi va ikkinchi merganniki tegib, uchinchi merganniki tegmaslik ehtimoli

P(k)=P(a)•P(b)•[1-P(c)]

1. Birinchi va uchinchi merganniki tegib, ikkinchi merganniki tegmaslik ehtimoli

P(l)=P(a)•[1-P(b)]•P(c)

1. Ikkinchi va uchinchi merganniki tegib, birinchi merganniki tegmaslik ehtimoli

P(z)=[1-P(a)]•P(b)•P(c)

1. Aniq (faqat) bittasiniki nishonga tegish ehtimoli

P(x)=P(g)+P(h)+P(j)

1. Hech bo'lmaganda ( kamida) bittasining nishonga tekkizish ehtimoli

P(v)=1-P(d)

11.Aniq (faqat) 2 tasining nishonga tekkizish ehtimoli

P(n)=P(k)+P(l)+P(z)

1. Hech bo'lmaganda ( kamida) ikkitasining nishonga tekkizish ehtimoli

P(m)=P(n)+P(f)

Qaysi savol kerak bo'lsa fikr bildirishda qoldiring

Yutqazganimizda ham muhimi olimpiadaga chiqdik ?